A 2000 kg truck moving at 20 m/s runs into a concrete wall and stops. What is the magnitude the work done on the truck?

The work done is, E = 20,000 J

Explanation:

Given that,

The mass of the truck, m = 2000 Kg

The velocity of the truck, v = 20 m/s

The work done by the truck on colliding with the concrete wall is, W = ?

A body moving with a particular velocity has kinetic energy associated with it. The work done by the body to completely stop the moving body is equal to the kinetic energy.

Therefore,

K. E = E = 1/2 mv²

Substituting the given values in the above equation,

E = 0.5 x 2000 Kg x 20 m/s

= 20,000 J

Hence, the work done on the truck is, E = 20,000 J