Consider a neutron star of radius 10 km that spins with a period of 0.8 seconds. Imagine a person is standing at the equator of this neutron star. Calculate the centripetal acceleration of this person

a = 616850.28 m/s²

Explanation:

Given that,

The radius of the neutron star, r = 10 Km

= 10,000 m

The time period of the neutron star, T = 0.8 s

The centripetal acceleration is given by the formula,

a = v²/r

The linear velocity is given by the relation,

v = rω

The time taken to complete one complete rotation is given by the relation

T = 2π / ω

Where,

ω = 2π / T

Substituting v and ω into the equation for centripetal acceleration. It becomes

a = 4π²r/T²

Substituting the given values in the above equation

a = 4π² x 10000 / 0.8²

= 616850.28 m/s²

Hence, the centripetal acceleration of this person is, a = 616850.28 m/s²