Ask Question
13 December, 06:36

A boy in a pedal car is moving at a speed of 1.40 m/s at the start of a 2.00 m high and 12.4 m long incline. The total mass is 45.5 kg, air resistance and rolling resistance can be modeled as a constant friction force of 41.0 N, and the speed at the lower end of the incline is 6.90 m/s. Determine the work done (in J) by the boy as the car travels down the incline.

+4
Answers (1)
  1. 13 December, 06:50
    0
    W = 655J

    Explanation:

    Workdone = change in kinetic energy + change in potential energy - workdone against friction

    = 1/2m (v2²-v1²) + mg (h2 - h1) + Ff*d

    Given

    m = 45.5kg

    v1 = 1.40m/s

    v2 = 6.90m/s

    h1 = 2.00m

    h2 = 0m (bottom of the incline)

    Ff = 41N frictional force

    d = 12.4m

    Workdone = 1/2*45.5 * (6.90²-1.40²) + mg (0 - 2.00) + 41*12.4

    Workdone = 655J

    Ff * d = work done against friction.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A boy in a pedal car is moving at a speed of 1.40 m/s at the start of a 2.00 m high and 12.4 m long incline. The total mass is 45.5 kg, air ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers