An electric field of intensity 3.0kN is applied along the x axis. Calculate the electric flux through a rectangular plane 0.350m wide and 0.700 m long if the following conditions are true: a) the plane is parallel to the yz plane b) The plane is parallel to thte xy plane c) The plane contains the y axis and its normal makes an angle of 30 degrees with the x axis.

Area of plane =.35 x. 7 = 0.245 m²

a) When plane is perpendicular to field (plane is parallel to yz plane.)

Flux = field x area

3000 x. 245 = 735 weber

b) When plane is parallel to xy plane, the plane also becomes parallel to electric field so no flux will pass though the given plane.

Flux through the plane = 0

c) Since normal to the plane makes 30 degree with x axis, it will also make 30 degree with direction of the field.

Flux through the plane

= electric field x area x cos 30

3000 x. 245 x. 866

636.51 weber.