Given a particle that has the velocity v (t) = 3 cos (mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find the displacement at 2 seconds.

a) V = 3 cos (0.5t)

differentiating with respect to t

dv / dt = - 3 x. 5 sin0.5t

= - 1.5 sin0.5t.

acceleration = - 1.5 sin 0.5t

when t = 3 s

acceleration = - 1.5 sin 1.5

= - 1.496 ms⁻²

v = 3 cos. 5t

b) dx/dt = 3 cos 0.5 t

dx = 3 cos 0.5 t dt

integrating on both sides

x = 3 sin. 5t /.5

x = 6 sin0.5t

At t = 2 s

x = 6 sin 1

x = 5.05 m