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4 November, 02:13

A cylinder contains 12liters of O2 at 20°c and 15atm. The temperature is raised to 35°c and volume is reduced to 8.5L. Calculate the final pressure. What will be the new pressure if the volume is doubled

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  1. 4 November, 02:42
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    Pressure : 11 atmosphere

    Explanation:

    According to gas equation P₁V₁/T₁ = P₂V₂/T₂

    Where P₁ is the initial pressure, V₁ is the initial volume and T₁ is the initial temperature

    P₂ is the final pressure, V₂ is the final volume and T₂ is the final temperature

    Thus P₁ = 15 atmosphere, V₁ = 12 liters and T₁ = 273 + 20 = 293 K

    P₂ = ?, V₂ = 8.5 liters, T₂ = 273 + 35 = 308 K

    From gas equation P₂ = P₁V₁T₂/T₁V₂ = 15 x 12 x 308 / 293 x 8.5

    = 22.3 atmosphere.

    If the volume is doubled

    The gas equation will be P₁V₁ = P₂V₂; because temperature is constant

    Here V₂ = 2 V₁ therefore pressure P₂ = P₁/2 = 22.3/2 = 11.1 atmosphere
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