The gage pressure in a liquid at a depth of 3 m is read to be 49 kPa. Determine the gage pressure in the same liquid at a depth of 9 m.

Answer: 147kpa

Explanation:

Guage pressure may be defined as the difference between the pressure of a system and its surrounding.

Guage pressure P can be written as.

P = pgh

Where p = density, g = acceleration due to gravity, h = depth

For, guage pressure P1 and P2.

P1 / P2 = p1g1h1/p2g2h2

Since it's the same liquid p1 = p2 and g1 = g2

P1/P2 = h1/h2

P2 = P1h2/h1

P1 = 49kpa

h1 = 3m

h2 = 9m

P2 = 49*9/3

P2 = 147kpa

Therefore, the gage pressure in the same liquid at a depth of 9 m is 147kpa.