0.5 kg of blood flows from the interior to the surface of John's body while he is exercising. The released energy is 2,000 J. The specific heat capacity of blood is 4,186 J/kgo C. What is the temperature difference between when the blood arrives at the body surface and returns back to the Interior of the body?

0.96°C

Explanation:

Specific heat capacity of a body is expressed as H = mcΔt

H = heat energy released by the body

m = mass of the body

c = specific heat capacity of the body

Δt = change in temperature of the body

Given H = 2000J, m = 0.5 kg, c = 4,186 J/kg° C.

Δt = H/mc

On substituting the given value;

Δt = 2000/4,186*0.5

Δt = 2000/2093

Δt = 0.96°C

The temperature difference between when the blood arrives at the body surface and returns back to the Interior of the body is 0.96°C