You measure the power delivered by a battery to be 5.83 W when it is connected in series with two equal resistors. How much power will the same battery deliver if the resistors are now connected in parallel across it

P = 23.32 W

Explanation:

In series

equivalent Resistance

R (eq) = R+R=2R

In parallel equivalent resistance

R (eq) = R*R / (R+R) = R/2

since.

power

P=V² / R

in series

⇒V = √ (P*R)

=√ (5.83*2R)

=√ (11.66R)

in parallel

P = V² / R (eq)

= (√ (11.66R) ²) / (R/2)

P=11.66 * R * 2/R

P = 23.32 W