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4 May, 10:06

A ray in oil (n = 1.52) reaches a boundary with water (n = 1.33) at 55.9 deg. Does it reflect internally or refract into the air?

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  1. 4 May, 13:12
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    Ray reflects internally

    Explanation:

    Given:

    Ray in oil (n1) = 1.52

    Ray in water (n2) = 1.33

    θ = 55.9°

    Computation:

    Step 1. Find critical angel (θc)

    Sinθc/Sin90° = Ray in water / Ray in oil

    Sinθc/1 = 1.33/1.52

    θc = 61°

    Since, θ = 55.9° is smaller than θc = 61°

    So, Ray reflects internally.
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