ListenA bullet traveling at 5.0 * 102 meters per second is brought to rest by an impulse of 50. newton-seconds. What is the mass of the bullet?2.5 * 104 kg1.0 * 101 kg1.0 * 10-1 kg1.0 * 10-2 kg

The mass of the bullet = 1.0 * 10⁻² kg

Explanation:

Impulse: The impulse of a body is defined as the product of force and time, or it can also be defined as the product of mass and change in velocity of that body. The S. I unit of impulse is newton - second or kg m/s

impulse = I = M (u-v)

Making M the subject of the equation above,

M = I / (u-v) ... Equation 1

Where I = impulse of the bullet, M = mass of the bullet, V = final velocity of the bullet, u = initial velocity of the bullet.

Given: I = 5.0 Newton - second, v = 0 (brought to rest), u = 5.0 * 10² m/s

Substituting these values into equation 1

M = 5 / (5.0 * 10²)

M = 1.0 * 10⁻² kg.

The mass of the bullet = 1.0 * 10⁻² kg