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17 June, 11:21

he drawing shows a plot of the force component F cos θ in the direction of the displacement s for one particular variable force, between a displacement of s = 0 m and s = d. What is the work done by the force when d = 7.32 m?

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  1. 17 June, 12:16
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    The question is incomplete.

    Note:The Curve is missing. So I assume force 200 N

    Explanation:

    Work Force Relationship

    "In Physics, work is defined as the result of a force moving an object a certain distance. Force is defined as a push or pull on an object resulting from the object's interaction with another object. Displacement is the distance and direction an object is moved. Force and work are directly proportional to each other, while force and displacement are indirectly propotional. The equation showing the relationship is W = Fd. W represents work measured in joules; F represents force in newtons; and d represents distance in meters."

    Since the force plotted is the force in the direction of the displacement, the work done by the force equals the area under the curve:

    W = (1/2) F*d

    W = 1/2 * 200 * d

    W = 100N * d

    if d=7.32

    W = (100) * (7.32)

    W=732N
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