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19 July, 13:05

A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. If the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?

Remember to identify all your data, write the equation, and show your work.

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Answers (1)
  1. 19 July, 14:27
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    Answer: 60.65 m

    Explanation

    Use eqation for distance for vertical throw (down)

    Vo=12m/s

    t=2.5

    S=Vot + gt^2/2

    S=12*2.5+9.81*2.5^2/2

    S=30+30.65

    S=60.65m
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