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28 December, 10:02

A diffraction grating contains 15,000 lines/inch. We pass a laser beam through the grating. The wavelength of the laser is 633 nm. On a screen 2.66m away, we observe spots of light. (a) How far (m) from the central maximum (m = 0) is the first-order maximum (m = 1) observed? (b) How far (m) from the central maximum (m = 0) is the second-order maximum (m = 2) observed? DO NOT calculate this using the

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  1. 28 December, 13:28
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    Recall the Diffraction grating formula for constructive interference of a light

    y = nDλ/w Eqn 1

    Where;

    w = width of slit = 1/15000in = 6.67x10⁻⁵in = 6.67x10⁻⁵ x 0.0254m = 1.69x10⁻⁶m

    D = distance to screen

    λ = wavelength of light

    n = order number = 1

    Given

    y1 = ? from 1st order max to the central

    D = 2.66 m

    λ = 633 x 10-9 m

    and n = 1

    y₁ = 0.994m

    Distance (m) from the central maximum (n = 0) is the first-order maximum (n = 1) = 0.994m

    Q b. How far (m) from the central maximum (m = 0) is the second-order maximum (m = 2) observed?

    w = width of slit = 1/15000in = 6.67x10⁻⁵in = 6.67x10⁻⁵ x 0.0254m = 1.69x10⁻⁶m

    D = distance to screen

    λ = wavelength of light

    n = order number = 1

    Given

    y1 = ? from 1st order max to the central

    D = 2.66 m

    λ = 633 x 10⁻⁹ m

    and n = 2

    y₂ = 0.994m

    Distance (m) from the central maximum (n = 0) is the first-order maximum (n = 2) = 1.99m
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