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29 June, 04:40

A friend on skis stands still on level ground, with dry 0.00°C with a coefficient of static friction of 0.0300. How hard would you have to push your friend in the forward horizontal direction to move him if your friend weighs 685 N?

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  1. 29 June, 05:51
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    20.6 N

    Explanation:

    Friction equals normal force times coefficient of friction.

    F = Fn μ

    On level ground, normal force equal weight.

    Fn = W

    Therefore:

    F = W μ

    F = (685 N) (0.0300)

    F = 20.6 N
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