A merry-go-round with a radius of 5.2 is rotating at 2.5 revolutions per minute. What is the linear velocity of a child sitting on the outside edge of the merry-go-round?

Question

Physics

Amari May

20 December, 18:17

A merry-go-round with a radius of 5.2 is rotating at 2.5 revolutions per minute. What is the linear velocity of a child sitting on the outside edge of the merry-go-round?

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Answers (1)

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Arabella Cervantes · Answer 1

The Linear velocity of a child sitting on the outside edge of the merry - go - round is 13 m/s

Explanation:

The given parameters are the radius of the merry go round which is 5.2 and the rotating speed is 2.5 revolutions per minute To find the linear velocity of a child sitting on the outside edge of the merry-go-round. we can use the equation v = rω where r is the radius and ω is the revolutions per minute that is the angular speed. When you substitute these values, the linear velocity would be 13 m/s