What is the x-component of the force on the charge located at x = 8 cm given that q = 1.1 μC in N?

Answer is = 12.3 x 10^6 N

Explanation:

We need to calculate force on the charge which is in Newtons:

Formula is = K q1q2/r^2

k is constant depeneds on the permitivity of the medium and its value is 9x10^9 Nm^2/C^2

q1 and q2 are charges and r is the distance between these two charges so just by putting values we get F = 9x10^9 x 1.1x10^-6 / (8x10^-2) ^2 (we get the above answer in newton)