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22 June, 02:46

Two children weighing 15 and 25 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. Where on the seesaw should a 10-kilogram child sit in order to achieve equilibrium? wo children weighing 15 and 25 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. Where on the seesaw should a 10-kilogram child sit in order to achieve equilibrium?

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  1. 22 June, 04:51
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    2 m

    Explanation:

    Let the child of mass 10 kg sits at a distance of d from axis on the side where the 15 kg child is sitting.

    According to the principle of moments

    Counter clockwise moments about O = clockwise moments about O

    15 x g x 2 + 10 x d x g = 25 x g x 2

    30 + 10 d = 50

    d = 2 m

    Thus, the 10 kg child should sit together with 15 kg at a distance of 2 m from the axis so that teh equilibrium is maintained.
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