A juggler throws a beanbag into the air with a speed of 1.0

How long does it take for the beanbag to reach its maximum height?

Round the answer to two significant digits.

Answer using a coordinate system where upward is positive.

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It takes for the beanbag 5/49 seconds to reach its maximum height

Explanation:

A juggler throws a beanbag into the air with a speed of 1.0

The initial speed is 1 m/s

The beanbag will reach to its maximum height

At the maximum height the speed equal to zero

The final speed is zero

The acceleration of gravity = - 9.8 m/s

We need to find how long it takes for the beanbag to reach its maximum

height

Lets use the rule: v = u + gt, where v is the final speed, u is the initial

velocity, t is the time and g is the acceleration of gravity

v = 0, u = 1, g = - 9.8

0 = 1 - 9.8 t

Add two sides by 9.8 t

9.8 t = 1

Divide both sides by 9.8

t = 5/49 seconds

It takes for the beanbag 5/49 seconds to reach its maximum height