A 13 g rubber stopper is swung in a horizontal circle with a radius of 0.85 m with a period of 0.65 s. (a) How fast is the stopper moving? (b) What is the centripetal acceleration of the stopper? (c) Find the centripetal force that is exerted on the stopper.

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Physics

Parks

9 November, 02:04

A 13 g rubber stopper is swung in a horizontal circle with a radius of 0.85 m with a period of 0.65 s. (a) How fast is the stopper moving? (b) What is the centripetal acceleration of the stopper? (c) Find the centripetal force that is exerted on the stopper.

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Dallas · Answer 1

(a) v = 2π r / t

v = 2π (0.85 m) / (0.65 s)

v = 8.2 m/s

(b) a = v² / r

a = (8.2 m/s) ² / (0.85 m)

a = 79 m/s²

(c) F = ma

F = (0.013 kg) (79 m/s²)

F = 1.0 N