A 2 kg soccer ball is traveling 28.62m/s when it hits the wall and bounces off of the wall with a velocity of 20 m/s. If the wall exerted an average force of 652.36N on the ball, how long was the ball in contact with the wall?

0.149 s or 0.15 s

Explanation:

let initially ball is moving towards left hence initial velocity = - 28.62 m/s

final velocity as ball moves right = + 20 m/s

force = rate of change in momentum

force = mass * change in velocity / time

or time = mass * change in velocity / force

time = 2 * (20 - (-28.62)) / 652.36

time = 2 * (20 + 28.62)) / 652.36

time = 2 * 48.62/652.36

time = 0.149 s or 0.15 s