A 5.80kΩ5.80kΩ resistor in a circuit has two mesh currents flowing through it. The first current measures 3.10mA3.10mA. The second current, flowing through the resistor in the opposite direction, measures 1.10mA1.10mA. What is the power dissipated by the resistor?

Question

Physics

Colt Vasquez

31 August, 09:59

A 5.80kΩ5.80kΩ resistor in a circuit has two mesh currents flowing through it. The first current measures 3.10mA3.10mA. The second current, flowing through the resistor in the opposite direction, measures 1.10mA1.10mA. What is the power dissipated by the resistor?

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Answers (1)

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Janiya · Answer 1

power = 23.2 mW

Explanation:

given data

resister r = 5.80 kΩ

current measures I1 = 3.10 m A

measure current I2 = 1.10mA

solution

we get here I total

I = current 1 - current 2

I = 3.10 - 1.10

I = 2 mA

so here power will be

power = I²*R ... 1

power = 2² * 5.80

power = 23.2 mW