Ask Question
21 July, 02:13

A mover pushes a 30.0 kg crate across a wooden floor at a constant speed of 0.75 m/s. If the coefficient of static friction for wood-on-wood is 0.20, what is the normal force exerted by the floor on the crate?

+5
Answers (1)
  1. 21 July, 02:53
    0
    294.3 N

    Explanation:

    In this situation, we are told that the crate is not accelerating in the horizontal plane. But also it is not accelerating in the vertical plane. Meaning that the sum of all vertical forces add up to zero.

    Fnet = ma

    Weight + Normal force = mass * acceleration

    - (30 kg * 9.81 m/s²) + Normal force = 30.0 kg * 0 m/s²

    Normal force = 294.3 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A mover pushes a 30.0 kg crate across a wooden floor at a constant speed of 0.75 m/s. If the coefficient of static friction for ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers