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26 July, 08:07

A metal sphere A has charge Q. Two other spheres, B and C, are identical to A except they have zero net charge. A touches B, then the two spheres are separated. B touches C, with C grounded during this contact, then those spheres are separated. Finally, C touches A and those two spheres are separated. How much charge is on each sphere?

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  1. 26 July, 11:28
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    A = Q/4 B=0 C=Q/4

    Explanation:

    The initial condition, is as follows:

    A=Q B=0 C=0

    When A is brought to contact with B, as both spheres are conductors, charge distribute evenly between the two spheres, so after this, the charges on the spheres are as follows:

    A = Q/2 B=Q/2 C=0

    If B touches C, while C is grounded, this supplies a infinite source of sink of charge, so both spheres lose any charge.

    At this stage, the charge distribution is as follows:

    A = Q/2 B=0 C=0

    Assuming C is not grounded, when finally touches A, the charge on A distributes evenly between A and C, so the final situation is as follows:

    A = Q/4 B=0 C=Q/4
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