The planet Krypton has a mass of 8.4 x 1023 kg andradius of 3.4 x 106 m.

What is the acceleration of an object in free fall near thesurface of Krypton? the gravitational constant is 6.6726 x10-11 N x m2 / kg2. Ans. in unitsof m/s2.

The acceleration of the object is 4.847m/s^2

Explanation:

Acceleration due to gravity g is given by:

g = (G*M) / R^2

Where G is gravitational constant

M is mass of object

R is radius

g = (6.6726*10^-11) * (8.4*10^23) / (3.4*10^6) ^2

g=5.605*10^13/1.156*10^13

g = 4.847m/s^2