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3 March, 20:59

A 55.0-gram lead bullet hits a steel plate, both initially at 24 °C. The bullet melts and splatters on impact. Assuming that the bullet receives 72% of its kinetic energy as heat energy, at what minimum speed must it be traveling to melt on impact? (The melting temperature of Lead is 327°C)

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  1. 4 March, 00:51
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    v = 609 m/s

    Explanation:

    mass of lead bullet, m = 55 g

    T1 = 24°C

    T2 = 327°C

    Let v be the velocity

    kinetic energy of bullet

    K = 1/2 mv^2 = 0.5 x 0.055 x v^2

    72 % of kinetic energy is used to melt the lead bullet.

    Heat gained by lead = m x c x ΔT + m x L

    where, c be the specific heat of lead and L be the latent heat of lead

    c = 536 J/kg°C

    L = 23000 J/kg

    0.0275 x v^2 = 0.055 (536 x 303 + 23000)

    v = 608.9 m/s

    v = 609 m/s
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