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6 March, 20:21

A spherical party balloon is being inflated with helium pumped in at a rate of 4 cubic feet per minute. How fast is the radius growing at the instant when the radius has reached 2 ft

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  1. 6 March, 21:27
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    0.159 ft/min

    Explanation:

    v = 4/3πr³

    dv/dt = 8

    dv/dt = 4/3π (3r²) (dr/dt)

    plugging the values

    8=4/3π (3r²) (dr/dt)

    dr/dt = 1 / (6.28) = 0.159 ft per min approx
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