A football place kicker kicks a ball with an initial horizontal velocity of 40 m/s and an initial vertical velocity of 30 m/s. Determine the resultant velocity (magnitude AND direction above the horizontal).

The resultant velocity, V=50<36.87°m/s

Explanation:

Vx = 40 m/s

Vy = 30 m/s

The magnitude of the resultant velocity is given by

Vx^ (2) + Vy^ (2) = V^2

〖40〗^ (2) + 〖30〗^2=V^2

V=√ (1600+900)

V=√2500

V = 50 m/s

For the direction

Vy=V sin⁡ø

30=50 sin⁡ø

ø=sin^ (-1) ⁡〖3/5〗

∅=36.87°

The resultant velocity, V=50<36.87°m/s