Ask Question
19 August, 20:00

A hanging block oscillating on the end of a spring passes through equilibrium at a speed of 2.0 m/s. It returns to equilibrium 0.75 s later. Calculate the total distance that it traveled between these two moments in its vibration. (Hint: How is the time related to the period? How is the distance traveled related to the amplitude?)

+5
Answers (1)
  1. 19 August, 22:17
    0
    1.5

    Explanation:

    From the question,

    velocity v = 2.0m/s

    Time t = 0.75secs

    Distance = ?

    Velocity = distance / time

    2.0 = d/0.75

    Crossmultipy

    d = 2.0 x 0.75

    = 1.5m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A hanging block oscillating on the end of a spring passes through equilibrium at a speed of 2.0 m/s. It returns to equilibrium 0.75 s ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers