The rigid link is supported by a pin at A and two A-36 steel wires, each having an unstretched length of 12 in. and cross-sectional area of 0.0125 in2. Determine the force developed in the wires when the link supports the vertical load of 350 lb.

Extension of the wire is not indicated

Explanation:

Young modulus (YM) = (stress/Strain); Tensile Stress/tensile Strain

=> YM * Strain = Stress=F/A; A is cross sectional area and F is the force

(YM * Strain * A) / 36 = F (Force developed in each wire)

F = (350 * e*0.0125) / 12