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14 July, 16:20

a ball is thrown at a 60.0 ° angle above the horizontal across level ground. it is thrown from a height of 2.00 m above the ground with a speed of 20.0 mis and experiences no appreciable air resistance. the time the ball remains in the air before striking the ground is closest to?

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  1. 14 July, 17:13
    0
    3.75 seconds

    Explanation:

    Given:

    y₀ = 2.00 m

    y = 0 m

    v₀ᵧ = 20.0 sin 60.0°

    aᵧ = - 9.8 m/s²

    Find: t

    y = y₀ + v₀ᵧ t + ½ aᵧ t²

    0 = 2.00 + (20.0 sin 60.0°) t + ½ (-9.8) t²

    0 = 2 + 10√3 t - 4.9 t²

    Solve with quadratic method:

    t = [ - 10√3 ± √ (300 - 4 (-4.9) (2)) ] / - 9.8

    t = (-10√3 ± √378.4) / - 9.8

    t ≈ - 0.218, 3.75

    Since t > 0, the ball lands after approximately 3.75 seconds.
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