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8 January, 07:50

A motorist driving a 1000-kg car wishes to increase her speed from 20 m/s to 30 m/s in 5 s. Determine the horsepower required to accomplish this increase. Neglect friction.

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  1. 8 January, 08:20
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    13.41 horsepower

    Explanation:

    Power: This can be defined as the rate at which energy is used up by a body. The S. I unit of power is Watt (W).

    The expression for power is given as,

    P = Ek/t ... Equation 1

    Where P = power, Ek = Kinetic Energy of the car, t = time.

    Recall that,

    Ek = 1/2mΔv² ... Equation 2

    Where m = mass of the car, Δv = change in velocity of the car.

    Substitute equation 2 into equation 1

    P = 1/2 (mΔv²) / t ... Equation 3

    Given:m = 1000 kg, Δv = 30-20 = 10 m/s, t = 5 s

    Substitute into equation 3

    P = 1/2 (1000*10²) / 5

    P = 10000 W.

    If,

    745.7 W = 1 hp,

    Then,

    10000 W = (10000/745.7) hp

    = 13.41 hp.

    P = 13.41 horsepower
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