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23 May, 00:52

A transformer has 500 primary turns and 9.7 secondary turns.

(a) If Vp is 120 V (rms), what is Vs with an open circuit?

(b) If the secondary now has a resistive load of 13 Ω, what is the current in the primary and secondary?

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  1. 23 May, 01:37
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    Answer: a) 2.33V b) Ip = 0.0035A, Is = 0.179A

    Explanation:

    The relationship formula between the Voltage, Number of turns and current in a transformer is given as

    Vp/Vs = Np/Ns = Is/Ip

    Vp is voltage in the primary coil

    Vs is voltage in the secondary coil

    Ns is number of turns in the secondary coil

    Np is number of turns in the primary coil

    Is is current in the secondary coil

    Ip is current in the primary coil

    a) substituting the values in the formula

    Vp/Vs = Np/Ns

    120/Vs = 500/9.7

    Vs = 120*9.7/500

    Vs = 2.33V

    b) since secondary now has a resistive load of 13 Ω, Using ohm's law to get current in the secondary

    V=IR

    Is = Vs/R

    Is = 2.33/13

    Is = 0.179A

    To get Ip, we will use the relationship Np/Ns = Is/Ip

    500/9.7 = 0.179/Ip

    Ip = 9.7*0.179/500

    Ip = 0.0035A
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