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7 April, 19:28

A 5 kg weight is hung from a vertical spring. The spring stretches by 5 cm. How much mass should be hung from the spring so it will stretch by 10

cm from its original length?

15 kg

25 kg

10 kg

20 kg

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Answers (1)
  1. 7 April, 19:39
    0
    10 kg

    Explanation:

    F = kx

    (5 kg) (9.8 m/s²) = k (0.05 m)

    k = 980 N/m

    F = kx

    m (9.8 m/s²) = (980 N/m) (0.10 m)

    m = 10 kg
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