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28 January, 14:07

A charge Q is distributed uniformly along the x axis from x1 to x2. What would be the magnitude of the electric field at x0 on the x-axis? Assume that ke = 1 4 π ǫ0 and x0 > x2 > x1 for a Coulomb constant of 8.98755 * 109 N · m2 / C 2

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  1. 28 January, 15:33
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    E = k Q 1 / (x₀-x₂) (x₀-x₁)

    Explanation:

    The electric field is given by

    dE = k dq / r²

    In this case as we have a continuous load distribution we can use the concept of linear density

    λ = Q / x = dq / dx

    dq = λ dx

    We substitute in the equation

    ∫ dE = k ∫ λ dx / x²

    We integrate

    E = k λ (-1 / x)

    We evaluate between the lower limits x = x₀ - x₂ and higher x = x₀-x₁

    E = k λ (-1 / x₀-x₁ + 1 / x₀-x₂)

    E = k λ (x₂ - x₁) / (x₀-x₂) (x₀-x₁)

    We replace the density

    E = k (Q / (x₂-x₁)) [ (x₂-x₁) / (x₀-x₂) (x₀-x₁) ]

    E = k Q 1 / (x₀-x₂) (x₀-x₁)
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