Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.0677 V. How much work is done by the electric force when a sodium ion (charge = + e) moves from the outside to the inside?

Answer: Recall that

Work (W) = - e * ∆V

Where

Charge of electron = 1.6 * 10^ - 19 c

And from the question we were given change in potential as = - 0.0677V

Work = - (1.6 * 10^-19) * (-0.0677)

Work = 1.0832 * 10^-20J

Therefore the work done by the electric force when a sodium ion (charge = + e) moves from the outside to the inside is 1.0832*10^-20