If the kinetic energy possessed by a man of 50kg is 625J, the speed of man is

Answer: v = 5 m/s

Explanation: Solution:

KE = 1/2 mv²

Derive to find v.

v = √ 2KE / m

Substitute the values

v = √2x 625 J / 50 kg

= √ 1250 J / 50 kg

= √ 25 kg. m/s / kg

= 5 m/s

Unit for J can be expressed in kg. m/s so we cancel kg and the remaining unit is m/s.