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17 July, 19:31

A car with a mass of 1,000 kg moving with an initial velocity of 8 m/s is brought to rest by colliding with a truck. The collisions takes place over a time span of 0.2 s. Calculate the force exerted on the car

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  1. 17 July, 22:22
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    -40,000 N

    Explanation:

    First, use the kinematics equation v (f) = v (i) + at. Final velocity is 0, initial is 8, and time is 0.2 seconds. Solving for a, you get - 40 m/s^2. Then, use Newton's second law, F=ma, to find the force. F = (1000) (-40) = - 40,000 N.
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