In a vacuum, two particles have charges of q1 and q2, where q1 = + 4.2C. They are separated by a distance of 0.31 m, and particle 1 experiences an attractive force of 4.5 N. What is the value of q2, with its sign?

Question

Physics

Regan Coleman

1 November, 01:25

In a vacuum, two particles have charges of q1 and q2, where q1 = + 4.2C. They are separated by a distance of 0.31 m, and particle 1 experiences an attractive force of 4.5 N. What is the value of q2, with its sign?

+2

Answers (1)

Know the Answer?

Cheerio · Answer 1

11.44pC.

Explanation:

F = kq1q2/r^2

q2 = Fr^2/kq1

= 4.5 x 0.31^2/4.2x 9 x 10^9

= 1.144 x 10^-11C

= 11.44pC

The sign is minus since they attracted to each other