The planet Jupiter has a mass that is equal to 318 times Earth's mass, an orbital radius of 5.21 AU, and an orbital velocity of 13.1 km/s. Earth's orbital velocity is 29.8 km/s. What is the ratio of Jupiter's orbital angular momentum to that of Earth's?

Answer: 729

Explanation:

Mass of Jupiter / mass of earth = 318

Velocity of Jupiter / velocity of earth = 13.1 / 29.8 = 0.440

Orbital radius of Jupiter / orbital radius of earth = 5.21

Angular momentum is given by;

Am = mass * velocity * radius = mvr

Therefore,

Aj/Ae = 318*0.44*5.21 = 728.98

Approximately = 729

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