A bicycle tire contains 2.00 L of gas at an absolute pressure of 7.00 * 10 5 N/m 2 and a temperature of 18.0 °C. What will its pressure be if you let out an amount of air that has a volume of 100 cm 3 at atmospheric pressure? Assume tire temperature and volume remain constant.

The final pressure will be 6.99 N/m^ 2

Explanation:

Initial volume of tire = 2.00 L

Initial pressure of the tire = 7.00 * 10 5 N/m 2

Initial temperature of tire 31 °C

P1V1 = P2V2

7.00 * 10 5 N/m 2 * V1 = 101325*100 → V1 = 1.45*10^ (-5) m^3 = 1.45*10^ (-2) L

Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)

pressure of released gas filling the entire 2 L = 2 L / (7.00 * 10^5 N/m^ 2 * 1.45*10^ (-5) m^3) = 1.197 * 10^ (-4) N/m^2

New pressure = 7.00 * 10^5 N/m^2 - 1.197 * 10^ (-4) N/m^2

= 6.99 N/m^ 2