Workmen are trying to free an SUV stuck in the mud. To extricate the vehicle, they use three horizontal ropes, producing the force vectors shown in the figure. (Figure 1) Take F1 = 914N, F2 = 704N, and F3 = 399N. Part A Find the x components of each of the three pulls. Enter your answer as three numbers, separated with commas. F1x, F2x, F3x = N SubmitMy AnswersGive Up Try Again Part B Find the y components of each of the three pulls. Enter your answer as three numbers, separated with commas. F1y, F2y, F3y = N SubmitMy AnswersGive Up Try Again Part C Use the components to find the magnitude of the resultant of the three pulls. F? = N SubmitMy AnswersGive Up Try Again Part D Use the components to find the direction of the resultant of the three pulls. Enter your answer as the angle counted from + x axis in the counterclockwise direction.

Question

Physics

Niko Reynolds

25 September, 16:28

Workmen are trying to free an SUV stuck in the mud. To extricate the vehicle, they use three horizontal ropes, producing the force vectors shown in the figure. (Figure 1) Take F1 = 914N, F2 = 704N, and F3 = 399N. Part A Find the x components of each of the three pulls. Enter your answer as three numbers, separated with commas. F1x, F2x, F3x = N SubmitMy AnswersGive Up Try Again Part B Find the y components of each of the three pulls. Enter your answer as three numbers, separated with commas. F1y, F2y, F3y = N SubmitMy AnswersGive Up Try Again Part C Use the components to find the magnitude of the resultant of the three pulls. F? = N SubmitMy AnswersGive Up Try Again Part D Use the components to find the direction of the resultant of the three pulls. Enter your answer as the angle counted from + x axis in the counterclockwise direction.

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Answers (1)

Know the Answer?

Mylee Ferguson · Answer 1

Fx = (783.451, 373.063, 240.124, 240.124) N

Fy = (470.745, 597.026, 318.66)

Fres = 768.216

Theta = 77.2 degrees from + x

Explanation:

F1 = 914N; F2 = 704N; F3 = 399N

Part A

Fx1 = F1*cos (A) = 914*cos (31) = + 783.451 N

Fx2 = F2*sin (B) = 704*sin (32) = - 373.063 N

Fx3 = F3*cos (C) = 399*cos (53) = - 240.124 N

Sum of Fx = + 170.26 N

Part B

Fy1 = F1*sin (A) = 914*sin (31) = + 470.745 N

Fy2 = F2*cos (B) = 704*cos (32) = + 597.026 N

Fy3 = F3*sin (C) = 399*sin (53) = - 318.66 N

Sum of Fy = + 749.111 N

Part C

Fres = sqrt (Fx^2 + Fy^2)

Fres = sqrt (170.26^2 + 749.111^2)

Fres = 768.216 N

Part D

Angle = arctan (Fy/Fx)

Angle = arctan (749.111/170.26)

Angle = 77.2 degrees