A 4.2 cm diameter circular loop of wire is in a 1.14 T magnetic field. The loop is removed from the field in 0.18 s. Assume that the loop is perpendicular to the magnetic field. What is the average induced emf?

Given Information:

Diameter of loop = d = 4.2 cm = 0.042 m

Magnetic field = B = 1.14 T

Time = Δt = 0.18 s

Required Information:

EMF = ?

Answer:

EMF = 0.417 V

Explanation:

The Faraday's Law of Induction relates induced EMF and the time rate of change of magnetic flux which is given by

EMF = - ΔФ/Δt

EMF = - AΔB/Δt

Where A is the area of circular loop and ΔB is the change in magnetic field

A = πr²

A = π (d/2) ²

A = π (0.042/2) ²

A = 0.0659 m²

EMF = - 0.0659 * (0 - 1.14) / 0.18

EMF = - 0.0659 * (-1.14) / 0.18

EMF = 0.417 V

Therefore, the average induced EMF in circular loop of wire is 0.417 Volts