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18 October, 07:26

A car is travelling at a speed of 21m/s. It accelerates at an average rate of 3m/s^2 for a time

of 4 seconds. Find the distance it travels.

Answers (1)
  1. R
    18 October, 08:35
    0
    S = 108m

    Explanation:

    According to Second Law of Motion:

    S = Vi*t + 0.5*a*t^2

    Vi = 21m/s

    a = 3m/s^2

    t = 4s

    Putting all values in Equation

    S = 21*4 + 0.5*3*4^2

    S = 84 + 24

    S = 108m
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