Ask Question
16 September, 23:48

The acceleration of gravity at the surface of Moon is 1.6 m/s2. A 5.0 kg stone thrown upward on Moon reaches a height of 20 m. (a) Find its initial velocity. (b) What is the time of flight to reach the max height

+5
Answers (1)
  1. 17 September, 01:40
    0
    (a) 8 m/s

    (b) 5 s

    Explanation:

    (a)

    Using,

    V² = U²+2gh ... Equation 1

    Where V = final velocity, U = Initial velocity, g = acceleration due to gravity on the surface of the moon, h = height reached.

    Given: V = 0 m/s (At it's maximum height), g = - 1.6 m/s² (as its moves against gravity), h = 20 m.

    Substitute into equation 1

    0 = U²+[2*20 * (-1.6) ]

    -U² = - 64

    U² = 64

    U = √64

    U = 8 m/s.

    (b)

    V = U + gt ... Equation 2

    Where t = time to reach the maximum height.

    Given: V = 0 m/s (At the maximum height), g = - 1.6 m/s² (Moving against gravity), U = 8 m/s.

    Substitute into equation 2

    0 = 8 + (-1.6t)

    -8 = - 1.6t

    -1.6t = - 8

    t = - 8/-1.6

    t = 5 s.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The acceleration of gravity at the surface of Moon is 1.6 m/s2. A 5.0 kg stone thrown upward on Moon reaches a height of 20 m. (a) Find its ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers