Ask Question
28 October, 03:41

A water molecule perpendicular to an electric field has 1.40*10-21 J more potential energy than a water molecule aligned with the field. The dipole moment of a water molecule is 6.2*10-30Cm.

What is the strength of the electric field?

Express your answer with the appropriate units.

+3
Answers (1)
  1. 28 October, 06:05
    0
    The strength of the electric field is 2.258 x 10⁸ N/C

    Explanation:

    Potential energy = - p*ECosθ

    where;

    d is the dipole moment

    E is the electric field

    θ is the angle of inclination

    →When the water molecules is perpendicular to the field, θ = 90° and potential energy = p*ECosθ = d*ECos0 = 0

    Total potential energy = 0 + 1.40*10⁻²¹J, since it is 1.40*10⁻²¹J more

    →When the water molecules is aligned to the field, θ = 0°

    potential energy = - p*ECosθ

    dipole moment, p = 6.2*10⁻³⁰Cm

    = - (6.2*10⁻³⁰) * (E) Cos0

    0 + 1.40*10⁻²¹ J = - (6.2*10⁻³⁰) * (E),

    E = (1.40*10⁻²¹ J) / (6.2*10⁻³⁰)

    E = 2.258 x 10⁸ N/C

    Therefore, the strength of the electric field is 2.258 x 10⁸ N/C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A water molecule perpendicular to an electric field has 1.40*10-21 J more potential energy than a water molecule aligned with the field. ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers