A proton (rest mass 1.67*10-27kg) is moving at 0.905 c. Find the momentum of the proton. Express your answer with the appropriate units.

P = 4.52 x 10⁻¹⁹ kg. m/s

Explanation:

Given that

m = 1.67 x 10⁻²⁷ kg

V = 0.905 C

We know that

C = 3 x 10 ⁸ m/s

Therefore, V = 0.905 x 3 x 10 ⁸ m/s

V = 2.71 x 10 ⁸ m/s

The linear momentum P is given as

P = m V

P = 1.67 x 10⁻²⁷ x 2.71 x 10 ⁸ kg. m/s

P = 4.52 x 10⁻¹⁹ kg. m/s

Therefore the answer will be 4.52 x 10⁻¹⁹ kg. m/s.