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24 May, 02:45

A 5kg ‏ Of copper specific heat capacity = 385j/kg C at 20 c is given 46200 j of energy what will be the final temperature

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  1. 24 May, 05:49
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    T_f = 44 [C]

    Explanation:

    The following heat transfer equation is used to solve this type of problem.

    Q = m*Cp * (T_f - Ti)

    Q = 46200 [J]

    Cp = 385 [J/kg*C]

    m = 5 [kg]

    Ti = 20 [C]

    Now replacing:

    46200 = 5*385 * (T_f - 20)

    46200 = 1925*T_f - 38500

    84700 = 1925*T_f

    T_f = 44 [C]
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