In 2005 a planet was found revolving about a distant sunlike star in 4.01 days. The radius of its orbit is 2 comma 600 comma 000 mi. What is its linear velocity (in mi/h) about its star?

Answer: linear velocity = 169,745.2mi/hr

Explanation:

Given: radius of orbit = 2,600,000mi

Time taken for orbit = 4.01 days = 4.01 * 24 hrs = 96.24hrs

Linear velocity = distance travelled/time

distance travelled = circumference of orbit = 2πr

= 2π * 2,600,000mi

= 16336281.8mi

Linear velocity = 16336281.8 / 96.24hrs

= 169745.2mi/hr