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1 October, 20:07

You push down on the car to provide more friction for the tires allowing the cars tires to propel it forward 5 meters. How much work do you do?

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  1. 1 October, 22:45
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    The work done by you, W = 9800 J

    Explanation:

    Given data,

    The displacement of the car, S = 5 m

    Let the mass of the car be, m = 2000 kg

    Let the coefficient of static friction be 0

    Hence, no frictional force is acting on the tire and ground.

    Let, you push down the car to provide more friction, μₓ = 0.1 (you can change the value)

    In order to provide the static friction, you push down the car is equal to the static friction force,

    Fₓ = μₓ · η

    Where,

    η - normal force acting on the car (mg)

    Substituting the values,

    Fₓ = 0.1 x 2000 x 9.8

    = 1960 N

    Therefore work done,

    W = Fₓ x S

    = 1960 N x 5 m

    = 9800 J

    Hence, the work done by you, W = 9800 J
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